đề dài nên T giải câu a thôi bn tự làm tiếp mấy câu khác nhé 

2x^2 - 2y^2 - 6x - 6y 

= 2(x^2-y^2) - 6(x+ y) 

= 2(x-y)(x+y) - 6(x+y) 

= (2(x-y)-6) (x+y)

ko biết

Bài 2: 

a: \(3x^2-3xy=3x\left(x-y\right)\)

b: \(x^2-4y^2=\left(x-2y\right)\left(x+2y\right)\)

c: \(3x-3y+xy-y^2=\left(x-y\right)\left(3+y\right)\)

d: \(x^2-y^2+2y-1=\left(x-y+1\right)\left(x+y-1\right)\)

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a) \(3xy-6xy^2=3xy\left(1-2y\right)\)

b) \(3x^3+6x^2+3x=3x\left(x^2+2x+1\right)=3x\left(x+1\right)^2\)

c) \(x^3-x^2+2\)

d) \(x^2+4x+4-y^2=\left(x^2+4x+4\right)-y^2=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\)

e) \(x^3+4x^2+4x=x\left(x^2+4x+4\right)=x\left(x+2\right)^2\)

f) \(x^2+2x+1-9y^2=\left(x+1\right)^2-\left(3y\right)^2=\left(x-3y+1\right)\left(x+3y+1\right)\)

g) \(6x^2-12x=6x\left(x-2\right)\)

h) \(x^3-2x^2+x=x\left(x^2-2x+1\right)=x\left(x-1\right)^2\)

i) \(x^2-2xy+y^2-9=\left(x-y\right)^2-3^2=\left(x-y-3\right)\left(x-y+3\right)\)

k) \(2x^3+2x^2y-4xy^2=2x\left(x^2+xy-2y^2\right)\)

l) \(x^3-7x^2+9x+3x^2-21x+27=x\left(x^2-7x+9\right)+3\left(x^2-7x+9\right)=\left(x+3\right)\left(x^2-7x+9\right)\)

Phân tích đa thức thành nhân tử

a. \(12x^3y-24x^2y^2+12xy^3\)

\(=12xy\left(x^2-2xy+y^2\right)\)

\(=12xy\left(x-y\right)^2\)

b. \(x^2-6x+xy-6y\)

\(=x\left(x-6\right)+y\left(x-6\right)\)

\(=\left(x+y\right)\left(x-6\right)\)

c. \(2x^2+2xy-x-y\)

\(=x\left(2x-1\right)+y\left(2x-1\right)\)

\(=\left(x+y\right)\left(2x-1\right)\)

d. \(x^3-3x^2+3x-1\)

\(=\left(x-1\right)^3\)

e. \(x^2-2xy-x^2-4y^2\)

\(=-2xy-4y^2\)

\(=-2y\left(x+2y\right)\)

g. \(x^2-2x+1-16\)

\(=\left(x-1\right)^2-4^2\)

\(=\left(x-1-4\right)\left(x-1+4\right)\)

a,2x²-7x+6=(2x²-4x)-(3x-6)
=2x(x-3)-3(x-2)=(x-2)(2x-3)
b,x²+x-6=(x²+3x)-(2x+6)
=x(x-3)-2(x-3)=(x-3)(x-2)
c,x³+3x²+6x+4=x³+x²+2x²+2x+4x+4
=(x+1)(x²+2x+4)
d,x¹⁰+x⁵+1=(x¹⁰-x)+(x⁵-x²)+(x²+x+1)
=x((x³)³-1)+x²(x³-1)+(x²+x+1)
=x(x³-1)(x⁶+x³+1)+x²(x-1)(x²+x+1)+(x²+x+1)
=x(x-1)(x²+x+1)+x²(x-1)(x²+x+1)+(x²+x+1)
(x²+x+1)(x²-x+x³-x²+1)
e,(12x²-12xy+3y²)-10x(2x-y)=3(4x²-4xy+y²)-10x(2x-y)
=3(2x-y)²-10x(2x-y)=(2x-y)(6x-3y-10x)=(2x-y)(-4x-3y)

phân tích đa thức thành nhân tử

a,2x^2-7x+6
b,x^2+x-6
c,x^3+3x^2+6x+4
d,x^10+x^5+1
e,(12x^2-12xy+3y^2)-10x(2x-y)

\(2x^2-7x+6\)

\(=2x^2-3x-4x+6\)

\(=x\left(2x-3\right)-2\left(2x-3\right)\)

\(=\left(x-2\right)\left(2x-3\right)\)

a/ \(=3y^2-6y-2x+1\)

b/ \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

c/ \(=\left(2-x\right)^3\)

d/ \(=xy^2+x^2y+3xy+x^2y+x^3+3x^2-3xy-3x^2-9x\)

\(=xy\left(y+x+3\right)+x^2\left(y+x+3\right)-3x\left(y+x+3\right)\)

\(=\left(xy+x^2-3x\right)\left(y+x+3\right)=x\left(y+x-3\right)\left(y+x+3\right)\)

e/ \(=xy-x^2+2x-y^2+xy-2y\)

\(=x\left(y-x+2\right)-y\left(y-x+2\right)=\left(x-y\right)\left(y-x+2\right)\)

a) =(2x+3y-1)²

b)=-(x-1)³

c)=-(x³-6x²+12x-8)=-(x-2)³

d)x3 + 2x2y + xy2 – 9x

    = x(x2 + 2xy + y2 -9)

    = x[(x2 + 2xy + y2) - 32]

    = x[(x + y)2 - 32]

    = x (x + y – 3)(x + y + 3)

e) 2x-2y-x²+2xy-y²=2(x-y)-(x-y)²=(x-y)(2-x+y)

a) 12xy( x² - 2xy + y²) = 12xy( x - y )²

b) ( x² + xy ) - ( 6x + 6y ) = x( x + y ) - 6( x + y )

= ( x + y )(x - 6)

c) ( 2x² + 2xy ) - ( x + y ) = 2x(x + y ) - ( x + y )

= (x + y )(2x - 1)

e) ( 3x² - 3y² ) - ( 12x + 12y ) = 3( x² - y² ) - 12( x + y)

= 3(x - y)(x + y) - 12(x + y) = ( x + y )(3x - 3y - 12)

= 3( x + y )(x - y -4)

g) \(\left[x\left(x+10\right)\right].\left[\left(x+4\right)\left(x+6\right)\right]\) + 128

= (x² + 10x).(x² + 10x + 24) + 128

Đặt x² + 10x + 12 = t

⇒ Biểu thức trên có dạng:

( t - 12 )(t + 12) + 128 = t² - 144 + 128 = t² - 16 = t² - 4²

= ( t - 4 )( t + 4) = (x² + 10x + 12 - 4 )(x² + 10x + 12 + 4)

= ( x² + 10x + 8)(x² + 10x + 16)

f) -2xy + 4y² = 2y( -x + 2y)

Có 2 phần g nha bạn. Mk chuyển phần cuối thành phần f.

Phần d do mk hơi ngu nên chưa nghĩ ra bạn thông cảm nha.